Answer
(a) $E=6.7\times 10^5N/C$
(b) stays the same
Work Step by Step
(a) We can find the electric field as follows:
$E=\frac{\sigma}{\epsilon_{\circ}}$
We plug in the known values to obtain:
$E=\frac{5.9\times 10^{-6}}{8.85\times 10^{-12}}$
$E=6.7\times 10^5N/C$
(b) $E=\frac{\sigma}{\epsilon_{\circ}}$. This equation shows us that the electric field doesn't depend on the thickness of the membrane. Hence, the answer to part (a) will stay the same.
