Answer
(a) $-2.6\times 10^{11}C$
(b) $1.4\times 10^8C$
Work Step by Step
(a) We know that
$Q_e=N(-e)$
$Q_e=\frac{M}{m_e}(-e)$
We plug in the known values to obtain:
$Q_e=\frac{1.5}{9.11\times 10^{-31}}(-1.6\times 10^{-19})$
$Q_e=-2.6\times 10^{11}C$
(b) We know that
$Q_e=N(e)$
$Q_e=\frac{M}{m_p}(e)$
We plug in the known values to obtain:
$Q_e=\frac{1.5}{1.67\times 10^{-27}}(1.6\times 10^{-19})$
$Q_e=1.4\times 10^8C$