Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 683: 7

Answer

$-1\times 10^6C$

Work Step by Step

We can find the required electric charge in carbon as $Q=N(-e)$ $\implies Q=(6nN_A)(-e)$ We plug in the known values to obtain: $Q=6(2)(6.022\times 10^{23})(-1.6\times 10^{-19})$ $Q=-1\times 10^6C$
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