Answer
$-7.8\times 10^{-12}C$
Work Step by Step
We can find the net charge as
$Q_{net}=N_e(-e)$
We plug in the known values to obtain:
$Q_{net}=4.9\times 10^7(-1.6\times 10^{-19})$
$Q_{net}=-7.8\times 10^{-12}C$
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