Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 647: 66

Answer

$11.21\frac{KJ}{K}$

Work Step by Step

We know that $100^{\circ}C=100+273=373K$ We can find the change in entropy as $\Delta S=\frac{\Delta Q}{T}$ We plug in the known values to obtain: $\Delta S=\frac{4181}{373}$ $\Delta S=11.21\frac{KJ}{K}$
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