Answer
$0.41KW$
Work Step by Step
As we know that
$COP=\frac{T_c}{T_h-T_c}=\frac{Q_c}{W}$
We plug in the known values to obtain:
$\frac{294}{305-294}=\frac{11KW}{W}$
$\implies W=0.41KW$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 647: 59
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