Answer
a) $Q_p=17KJ$
b) $Q_v=10KJ$
Work Step by Step
(a) We can find the required heat at constant pressure as follows:
$Q_p=\frac{5}{2}nR(T_f-T_i)$
$Q_p=\frac{5}{2}nR(2T_i-T_i)=\frac{5}{2}nRT_i$
We plug in the known values to obtain:
$Q_p=\frac{5}{2}(2.5)(8.31)(325)$
$Q_p=17KJ$
(b) We can find the required heat at constant volume as
$Q_v=\frac{3}{2}nRT_i$
We plug in the known values to obtain:
$Q_v=\frac{3}{2}(2.5)(8.31)(325)$
$Q_v=10KJ$
