Answer
(a) $0.95K$
(b) $0.57K$
Work Step by Step
(a) We know that
$Q_V=\frac{3}{2}nR\Delta T$
This can be rearranged as:
$\Delta T=\frac{2Q_V}{3nR}$
We plug in the known values to obtain:
$\Delta T=\frac{2(535)}{3(45)(8.31)}$
$\Delta T=0.95K$
(b) As $Q_P=\frac{5}{2}nR\Delta T$
This can be rearranged as:
$\Delta T=\frac{2Q_P}{5nR}$
We plug in the known values to obtain:
$\Delta T=\frac{2(535)}{5(45)(8.31)}$
$\Delta T=0.57K$
