Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 645: 34

Answer

(a) $1.7KJ$ (b) $1.0KJ$

Work Step by Step

(a) We know that $Q_p=\frac{5}{2}nR\Delta T$ We plug in the known values to obtain: $Q_p=\frac{5}{2}(3.5)(8.31)(23)$ $Q_p=1.7KJ$ (b) As $Q_V=\frac{3}{2}nR\Delta T$ We plug in the known values to obtain: $Q_V=\frac{3}{2}(3.5)(8.31)(23)$ $Q_V=1.0KJ$
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