Answer
(a) $1.7KJ$
(b) $1.0KJ$
Work Step by Step
(a) We know that
$Q_p=\frac{5}{2}nR\Delta T$
We plug in the known values to obtain:
$Q_p=\frac{5}{2}(3.5)(8.31)(23)$
$Q_p=1.7KJ$
(b) As $Q_V=\frac{3}{2}nR\Delta T$
We plug in the known values to obtain:
$Q_V=\frac{3}{2}(3.5)(8.31)(23)$
$Q_V=1.0KJ$