Answer
$W=1160J$
Work Step by Step
We can find the work done as
$W=Q-\Delta U$
$\implies W=Q-\frac{3}{2}nR\Delta T$
We plug in the known values to obtain:
$W=1210-\frac{3}{2}(1)(8.31)(276-272)$
$W=1160J$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 643: 4
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