Answer
$Q_D\lt Q_C\lt Q_B\lt Q_A$
Work Step by Step
We know that
$Q_{fusion}=\frac{Q_{removed}}{m}$
Now we find the heat of fusion for all four given liquids as follows:
$Q_A=\frac{33500}{0.1}=335KJ/Kg$
$Q_B=\frac{166000}{0.5}=332KJ/Kg$
$Q_C=\frac{31500}{0.250}=126KJ/Kg$
$Q_D=\frac{5400}{0.05}=108KJ/Kg$
We can arrange in increasing order of latent heat of fusion as follows:
$Q_D\lt Q_C\lt Q_B\lt Q_A$
