Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 17 - Phases and Phase Changes - Problems and Conceptual Exercises - Page 605: 31

Answer

$191K$

Work Step by Step

We can find the required temperature as follows: $v_{rms}=\sqrt{\frac{3RT}{M}}$ This simplifies to: $T=\frac{Mv_{rms}^2}{3R}$ We plug in the known values to obtain: $T=\frac{(329)^2}{3\times 8.314\times 1000}$ $T=191K$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.