Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 17 - Phases and Phase Changes - Problems and Conceptual Exercises - Page 604: 27

Answer

$632m/s$

Work Step by Step

We can find the rms velocity of $NH_3$ as follows: $rms \space of\space NH_3=\sqrt{\frac{3RT}{m}}$ We plug in the known values to obtain: $rms \space of\space NH_3=\sqrt{\frac{3(8.31)(273)}{0.017}}$ $rms \space of \space NH_3=632m/s$
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