Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 571: 97

Answer

$82C^{\circ}$

Work Step by Step

We know that $T_b=T-\frac{m_wc_w}{m_bc_b}(T_w-T)$ We plug in the known values to obtain: $T_b=22.5C^{\circ}-\frac{(1.1Kg)(4186J/Kg.K)}{(0.50Kg)(390J/Kg.K)}(20.0C^{\circ}-22.5C^{\circ})$ This simplifies to: $T_b=82C^{\circ}$
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