Answer
$(A)~107~ft,~7.8~in$
Work Step by Step
We know that
$\Delta L=\alpha L\Delta T$
$\implies \Delta L=(22\times 10^{-6}K^{-1})(107 \frac{5}{12}ft)(120-23^{\circ}C)$
We plug in the known values to obtain:
$\Delta L=0.229ft\times 12in/ft=2.8in$
Now we can find the required length as
$L=L_{\circ}+\Delta L$
$L=(107~ft,~5.0~in)+2.8in=107~ft,~7.8~in$
