Answer
$(B)~310^{\circ}C$
Work Step by Step
We know that
$\Delta L=\alpha L_{\circ}(T-T_{\circ})$
This can be rearranged as:
$T=T_{\circ}+\frac{\Delta L}{\alpha L_{\circ}}$
We plug in the known values to obtain:
$T=23C^{\circ}+\frac{8/12ft}{(22\times 10^{-6}K^{-1})(107 \frac{5}{12}ft)}$
$T=310^{\circ}C$
