Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 536: 104

Answer

$0.50KN,1.1\times 10^2lbs$

Work Step by Step

We know that $P=\frac{F}{A}$ This can be rearranged as: $F=PA$ We plug in the known values to obtain: $F=(0.50KPa)(34in)(46in)(\frac{1m}{39.37in})^2=0.50KN$ Now $F=0.505KN(\frac{224.8}{1KN})=1.1\times 10^2lbs$
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