Answer
(a) $94Pa$
(b) $0.0025\frac{m^3}{s}$
Work Step by Step
(a) The pressure difference can be determined as
$A=\frac{\pi D^2}{4}$
$A=\frac{\pi(0.052)^2}{4}=0.002124m^2$
Now $P_1-P_2=8\pi \eta \frac{vL}{A}$
We plug in the known values to obtain:
$P_1-P_2=8\pi \eta \frac{vL}{A}$
We plug in the known values to obtain:
$P_1-P_2=\frac{8\pi(0.00012)(1.2)(55)}{0.002124}=94Pa$
(b) The volume flow rate is given as
$Volume\space flow \space rate=Av$
We plug in the known values to obtain:
$Volume \space rate=0.00212(1.2)=0.0025\frac{m^3}{s}$
