Answer
$64Hz$
Work Step by Step
The fundamental frequency of the tube can be calculated as
$f_1=\frac{v}{2L}$
We plug in the known values to obtain:
$f_1=\frac{343}{2(2.7)}=64Hz$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 498: 117
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