Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 495: 68

Answer

$f_1=49Hz$

Work Step by Step

The frequency of an air column is equal to $$f_n=\frac{nv}{2L}$$ Since the tone is the fundamental frequency, $n=1$. This means that $$f_1=\frac{v}{2L}$$ Substituting known values of the speed of sound $v=343m/s$ and $L=3.5m$ yields a frequency of $$f_1=\frac{343m/s}{2(3.5m)}=49Hz$$
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