Answer
$147Hz$
Work Step by Step
We know that
$\Delta d=d_2-d_1=\sqrt{(2.80)^2+(4.30)^2}-2.80=2.331m$
Now we can find the required frequency as
$f=\frac{v}{\lambda}$
We plug in the known values to obtain:
$f=\frac{343}{2.33}$
$f=147Hz$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 494: 66
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