Answer
a) less time
b) $t=0.184s$
c) $t=0.174s$
Work Step by Step
(a) As $v=\sqrt{\frac{T}{\mu}}$, this equation shows that the speed of the wave (v) is directly proportional to the square root of the tension (T). Thus, if the tension in the string is increased then the speed of the wave will increase and as a result the wave takes less time to travel from one end to the other.
(b) We know that
$v=\sqrt{\frac{T}{u}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{9.0N}{3.37\times 10^{-3}Kg/m}}=51.7m/s$
Now $t=\frac{l}{v}$
$\implies t=\frac{9.5m}{51.7m/s}$
$t=0.184s$
(c) As $v=\sqrt{\frac{T}{\mu}}$
$\implies v=\sqrt{\frac{10.0N}{3.37\times 10^{-3}Kg/m}}=54.5m/s$
and $t=\frac{l}{v}$
We plug in the known values to obtain:
$t=\frac{9.5m}{54.5m/s}$
$\implies t=0.174s$
