Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 451: 103

Answer

$(B). 1700$

Work Step by Step

We know that $f=\frac{T-39}{13s}$ $\implies f_{75}=\frac{75-39}{13s}=2.77Hz$ similarly $f_{63}=\frac{63-39}{13s}=1.85Hz$ Now, the average frequency is $\frac{2.77+1.85}{2}=2.31Hz$ The number of chirps can be calculated as $N=ft_{total}$ $\implies N=(2.31)(12)(\frac{60s}{1min})$ $N=1700chirps$
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