Answer
(a) $0.017J$
(b) $0.34N$
Work Step by Step
(a) The maximum kinetic energy can be determined as
$K.E_{max}=\frac{1}{2}A^2\omega^2$
We plug in the known values to obtain:
$K.E_{max}=\frac{1}{2}(0.84)(0.100)^2(2.00)^2=0.017J$
(b) We know that
$F_{max}=m(A\omega^2)$
We plug in the known values to obtain:
$F_{max}=(0.84)(0.100)(2.00)^2=0.34N$
