Answer
(a) $1.1\frac{Km}{s^2}$
(b) $6.2\frac{m}{s}$
Work Step by Step
(a) We know that
$a_{max}=A\omega^2$
We plug in the known values to obtain:
$a_{max}=3.5(178s^{-1})^2=1.1\frac{Km}{s^2}$
(b) The maximum speed can be calculated as
$v_{max}=A\omega$
We plug in the known values to obtain:
$v_{max}=3.5(178s^{-1})=6.2\frac{m}{s}$
