Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 445: 9

Answer

(a) $T/2$ seconds (b) $3T/4$ seconds

Work Step by Step

The period is the time it takes for the particle to go from the amplitude, to the negative amplitude, back to the positive amplitude. This distance is $2A+2A=4A$. Therefore, to travel half that distance, $2A$, it must take $T/2$ s. To travel $3A$, it must take three-fourths the total period time, $3T/4$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.