Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 445: 8

Answer

(a) $4A$ (b) $10A$

Work Step by Step

The period is the time it takes for a particle to go through one full cycle of oscillation. One full cycle for a mass oscillating requires the mass to move from $A$ to $-A$ and then back to $A$. This total distance is $2A+2A=4A$. Since the distance traveled in $T$ s. is $4A$, the distance traveled in $5T/2$ s. is $\frac{5}{2}(4A)=10A$.
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