Answer
C is the maximum velocity of the motion, D is the angular frequency of the motion, the period is equal to $\frac{2π}{D}$ and the amplitude is equal to $\frac{C}{D}$.
Work Step by Step
Note that simple harmonic motion follows the formula $x(t)=Acos(ωt)$. Velocity is the derivative of position, so velocity must be $v(t)=−Aωsin(ωt)$, where A is the amplitude and ω is the angular frequency. Therefore, it can be concluded that C is the maximum velocity and D is the angular frequency. Since $−Aω=−C$, it can be concluded that the amplitude $A$ is equal to $\frac{C}{ω}$, or $\frac{C}{D}$, since omega is equal to D in the equation. Period and angular frequency are related using the formula $$T=\frac{2π}{ω}$$ Since ω=D, the period can be expressed as $\frac{2π}{D}$.
