Answer
a) greater than 24 hours
b) westward
c) 25.4 h
Work Step by Step
(a) We know that $T=Cr^{\frac{3}{2}}$. As the satellite is 1000 miles farther than a geosynchronous satellite, the value of $r$ is greater and hence the period is greater than 24 hours.
(b) We know that as the Earth moves eastward, objects with a period less than 1 day will appear to move eastward (as the satellite will move faster than the Earth's spin in the east direction). On the other hand, the objects having a period greater than 24 hours will move slower than that of the Earth's rotation and will appear to move westward.
(c) We know that
$T=2\pi \sqrt{\frac{R^3}{GM_E}}$
We plug in the known values to obtain:
$T=2\pi \sqrt{\frac{(4.39\times 10^7m)^3}{(6.67\times 10^{-11})(5.97\times 10^{24}Kg)}}$
$\implies T=25.4hr$
