Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 413: 82

Answer

a) $L_p=4.7\times 10^{30}Kg.\frac{m^2}{s}$ b) $L_a=4.7\times 10^{30}Kg.\frac{m^2}{s}$

Work Step by Step

(a) The angular moment at perihelion is given as $L_p=mv_pr_p$ We plug in the known values to obtain: $L_p=9.8\times 10^{14}(54,600)(8.823\times 10^{10})$ $L_p=4.7\times 10^{30}Kg.\frac{m^2}{s}$ (b) The angular moment at aphelion is given as $L_a=mv_ar_a$ We plug in the known values to obtain: $L_a=9.8\times 10^{14}(783)(6.152\times 10^{12})$ $L_a=4.7\times 10^{30}Kg.\frac{m^2}{s}$
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