Answer
(a) more
(b) $39.24m/s^2$
Work Step by Step
(a) We know that the gravitational acceleration is inversely proportional to the square of the radius and it is given that the radius of the planet is half of Earth's radius. Thus, the gravitational acceleration on the planet is more than that due to gravity on Earth.
(b) We can calculate the required gravitational acceleration as follows:
$g_p=\frac{GM_p}{R_p^2}$
$\implies g_p=\frac{GM_p}{(\frac{R_E}{2})^2}$
This simplifies to:
$g_p=\frac{4GM_E}{R_E^2}$
$\implies g_p=4g_E$
We plug in the known values to obtain:
$g_p=4(9.81m/s^2)$
$g_p=39.24m/s^2$
