Answer
a) $T=0.86N$
b) greater than in part (a)
c) $T=0.91N$
Work Step by Step
(a) We can find the tension in the string as follows:
$T=\frac{W}{2sin\theta}$
We plug in the known values to obtain:
$T=\frac{(0.16)(9.81)}{2sin66^{\circ}}$
$T=0.86N$
(b) We know that the shorter string will make a smaller angle and thus the tension will be greater as compared to that of part (a).
(c) We can find the required tension as follows:
$T=\frac{W}{2sin\theta}$
We plug in the known values to obtain:
$T=\frac{(0.16)(9.81)}{2sin60^{\circ}}$
$T=0.91N$
