Answer
$1.1m$
Work Step by Step
We know that
$\Sigma F_y=F_{front}+F_{rear}-mg=0$
$\implies mg=F_{front}+F_{rear}=3F_{front}$
Now $\Sigma \tau=F_{front}(3.2m)-mg(d)=0$
$\implies F_{front}(3.2)=3F_{front}(d)$
This simplifies to:
$d=\frac{1}{3}(3.2)=1.1m$
