Answer
Option (C) is correct.
Work Step by Step
We know that
$\omega=\sqrt{\frac{a_{cp}}{r}}$
We plug in the known values to obtain:
$\omega=\sqrt{\frac{49.05m/s^2}{1.905m}}$
This simplifies to:
$\omega=5.0743rad/s$
Now we convert it into rpm as
$(5.0743rad/s)(\frac{1rev}{2\pi rad})(\frac{60s}{1min})=48.5rpm$
Thus, the curve that coincides with $48.5rpm$ from the x-axis and 5gs from the y-axis is curve 3 and we see that option C is correct.