Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 331: 113

$\omega=48.4\frac{rev}{min}$

We know that $\omega=\sqrt{\frac{a_{cp}}{r}}$ We plug in the known values to obtain: $\omega=\sqrt{\frac{5\times 9.81}{6.25ft\times 0.305\frac{m}{ft}}}$ $\omega=\frac{5.07}{s}\times \frac{1 rev}{2\pi rad}\times \frac{60s}{min}$ $\omega=48.4\frac{rev}{min}$