Answer
a) $\Delta x=0.50\ m$
b) $\theta=2.4\ rotations$
Work Step by Step
(a) We know that
$\Delta x=\frac{1}{2}(1.0)$
$\Delta x=0.50\ m$
(b) We know that
$s=r\theta$
This can be rearranged as:
$\theta=\frac{s}{r}$
We plug in the known values to obtain:
$\theta=\frac{0.50}{\frac{1}{2}(0.065)}$
$\theta=15 rad\times \frac{1rev}{2\pi \space rad}$
$\theta=2.4\ rotations$