Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 330: 109

a) $\Delta x=0.50\ m$ b) $\theta=2.4\ rotations$

(a) We know that $\Delta x=\frac{1}{2}(1.0)$ $\Delta x=0.50\ m$ (b) We know that $s=r\theta$ This can be rearranged as: $\theta=\frac{s}{r}$ We plug in the known values to obtain: $\theta=\frac{0.50}{\frac{1}{2}(0.065)}$ $\theta=15 rad\times \frac{1rev}{2\pi \space rad}$ $\theta=2.4\ rotations$