Answer
$I=0.17Kg.m^2$
Work Step by Step
We know that
$I=mR^2(\frac{2gh}{v^2}-1)$
We plug in the known values to obtain:
$I=2.1(0.080)^2(\frac{2(9.81)^2(0.074)}{(0.33)^2}-1)$
$I=0.17Kg.m^2$
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