Answer
(a) $0.70m/s$ (b) The new velocity would double. (1.4 m/s)
Work Step by Step
(a) We know that
$\omega=3.0rev/s$
$\implies \omega=3\times 2\pi rad/s$
$\omega=6\pi rad/s$
Now $v=r\omega$
We plug in the known values to obtain:
$v=(3.7cm)(6\pi rad/s)$
This simplifies to:
$v=0.70m/s$
(b) We know that if the radius of the reel were doubled then the linear speed would also be doubled.
