Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 325: 34

Answer

(a) $1.18 rad/s$ (b) $10.0 m/s^2$ (c) Tension in the vine.

Work Step by Step

(a) The angular speed can be calculated as $\omega=\frac{v}{r}$ We plug in the known values to obtain: $\omega=\frac{8.50m/s}{7.20m}$ $\omega=1.18rad/s$ (b) The centripetal acceleration can be calculated as: $a_c=\frac{v^2}{r}$ We plug in the known values to obtain: $a_c=\frac{(8.50m/s)^2}{7.20m}$ $a_c=10m/s^2$ (c) We know that the vine exerts the force which is responsible for the person's centripetal acceleration.
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