Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 325: 32

Answer

$\omega=26rad/s$

Work Step by Step

We can determine the required angular speed as follows: $\omega=\frac{v}{r}$ We plug in the known values to obtain: $\omega=\frac{3.7m/s}{0.145m}$ $\implies \omega=26rad/s$
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