Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 324: 18

Answer

$t=28.1s$

Work Step by Step

(a) We know that $\alpha=\frac{\omega_f^2-\omega_i^2}{2(\theta-\theta_{\circ})}$ We plug in the known values to obtain: $\alpha=\frac{(0)^2-(6.35)^2}{2(14.2\times 2\pi)}=-0.226\frac{rad}{s^2}$ (b) As $\alpha=\frac{\omega_f-\omega_i}{t}$ This can be rearranged as: $t=\frac{\omega_f-\omega_i}{\alpha}$ We plug in the known values to obtain: $t=\frac{0-6.35}{-0.226}=28.1s$
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