Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 324: 17

Answer

$\Delta \theta=47\ rad$

Work Step by Step

We know that $\Delta \theta=\frac{1}{2}(\omega_i+\omega_f)t$ We plug in the known values to obtain: $\Delta \theta=\frac{1}{2}(11+28)(2.4)$ $\Delta \theta=47\ rad$
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