Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 324: 10

Answer

(a) $31.4~rad/s$ (b) $55~inches/s$ (c) same

Work Step by Step

(a) We can find the angular speed as follows: $\omega=\frac{2\pi}{T}$ We plug in the known values to obtain: $\omega=\frac{2\pi}{0.20s}$ $\omega=31.4rad/s$ (b) The linear speed can be determined as $v=r\omega$ We plug in the known values to obtain: $v=(1.75inch)(31.4rad/s)$ $v=55inches/s$ (c) Since we know that the angular speed is independent of the distance from the axis of rotation, the the angular speed will be the same as found in part(a).
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