Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 323: 3

Answer

(a) $1\frac{rev}{h}=2\pi\frac{rad}{hr}$ (b) $2\frac{rev}{day}=\frac{1 rev}{12 hours}=\frac{2\pi rad}{12 hr}=\frac{\pi}{6}\frac{rad}{hr}$

Work Step by Step

(a)As we know that the minute hand completes one revolution in one hour so its angular speed is $1\frac{rev}{h}=2\pi\frac{rad}{hr}$ (b) The hour hand completes two revolutions in a day (24 hours), so the angular speed of the hour hand is $2\frac{rev}{day}=\frac{1 rev}{12 hours}=\frac{2\pi rad}{12 hr}=\frac{\pi}{6}\frac{rad}{hr}$
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