Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 256: 58

Answer

$2.4\times10^6\;N$.

Work Step by Step

By symmetry, we know that the two forces have the same magnitude F. Write Newton’s second law for the vertical direction. $$\Sigma F_y=Fsin\;5^{\circ}+ Fsin\;175^{\circ}-F_{buttress}=0$$ $$F=\frac{F_{buttress}}{ 2\;sin\;5^{\circ}}=\frac{420000\;N}{ 2\;sin\;5^{\circ}}=2.4\times10^6\;N$$
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