Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 256: 52

Answer

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Work Step by Step

a. Calculate the stress on the bone. $$\frac{F}{A}=\frac{3.3\times10^4 \;N}{3.6\times10^{-4}m^2}=9.167\times10^7\;N/m^2$$ This is less than the compressive strength of bone, so the bone does not break. b. The strain is $\frac{stress}{E}=\frac{9.167\times10^7\;N/m^2}{15\times 10^9 N/m^2}=6.11 \times 10^{-3}$ Use the definition of strain to find the amount by which it is shortened. $$\Delta \mathcal{l}=\mathcal{l}_o(strain)$$ $$=(22cm)( 6.11 \times 10^{-3})=1.3\times 10^{-3}m$$
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