Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems: 50

Answer

$5.1 \times 10^4 N$.

Work Step by Step

Set the compressive strength of bone (Table 9-2) equal to the applied stress on the bone. Compressive strength = $\frac{F_{max}}{A}$ $$F_{max}=(170\times 10^6 N/m^2)(3.0 \times 10^{-4}m^2)= 5.1 \times 10^4 N $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.