Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems: 41

Answer

a. $1.8 \times 10^5 N/m^2$ b. $3.5 \times 10^{-6}$

Work Step by Step

a. The stress is $\frac{F}{A}=\frac{(25000 kg)(9.80 m/s^2)}{1.4m^2}=1.8 \times 10^5 N/m^2$ b. The strain is $\frac{stress}{E}=\frac{175000N/m^2}{50\times 10^9 M/m^2}=3.5 \times 10^{-6}$
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