Answer
See answers.
Work Step by Step
Find the amount of stretch by using equation 9–4.
$$\Delta \mathcal{l}=\frac{1}{E}\frac{F}{A}\mathcal{l}_o$$
$$=\frac{1}{3 \times 10^9 N/m^2}\frac{275 N}{\pi (0.0005 m)^2}(0.300m) $$
$$=3.5 \times 10^{-2}m$$