Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 38

Answer

10.9 meters farther.

Work Step by Step

From the textbook, on page 240, “An object whose center of gravity above its base of support will be stable if a vertical line projected downward from the center of gravity falls within the base of support.” From the given information, the base of support is a circle of radius 7.7 m. The tower will be unstable if the CG is more than 7.7 meters off center. which means that the top is 2(7.7m) = 15.4 m off center. The top is currently 4.5m off center, so it would have to move 15.4 m– 4.5m = 10.9 m farther to be unstable.
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